Discover what happens when a number approaches another number.
Can you approach a point from two directions?
Imagine standing in front of a door marked with the number 2.
You can approach the door from the left side or from the right side.
Before moving ahead, think:
Is 1.99 smaller or greater than 2?
Experiment 1: Approach from the left
Move the slider. Watch x get closer to 2 from smaller values.
As x gets closer to 2 from the left, the output gets closer to 8.
Experiment 2: Approach from the right
Now approach 2 from numbers that are greater than 2.
As x gets closer to 2 from the right, the output also gets closer to 8.
Compare both directions
We are studying the same function from two different sides.
| From the left | From the right |
|---|---|
| 1.9 | 2.1 |
| 1.99 | 2.01 |
| 1.999 | 2.001 |
| 7.7 | 8.3 |
| 7.97 | 8.03 |
| 7.997 | 8.003 |
What do you notice?
Mathematics gives these directions special names
We use different symbols to describe the two approaches.
Left-hand limit
The small minus sign means x approaches 2 from values smaller than 2.
Right-hand limit
The small plus sign means x approaches 2 from values greater than 2.
See both directions on a graph
Consider the function f(x) = 3x + 2. Its graph is a straight line.
Both paths reach the same height as they approach x = 2. That height is 8.
What if the two directions give different answers?
Now consider a new function:
Can the two-sided limit exist in this example?
Your discovery: when does a limit exist?
You have now seen two possible situations.
Situation A: Both sides approach the same value
Situation B: Both sides approach different values
This equality is the condition for a two-sided limit to exist.
Final challenge
If the left-hand limit is 5 and the right-hand limit is also 5, what is the two-sided limit?
A strange result appears
Consider this function:
We want to find what happens when x approaches 2.
Try putting x = 2 directly into the expression.
We have reached a strange result. The numerator is zero, and the denominator is also zero.
What do you think 0 / 0 means?
Look closer instead of substituting
When x is very close to 2, but not exactly 2, calculate the function.
| x | Numerator | Denominator | Output |
|---|---|---|---|
| 1.9 | -0.39 | -0.1 | 3.9 |
| 1.99 | -0.0399 | -0.01 | 3.99 |
| 1.999 | -0.003999 | -0.001 | 3.999 |
| 2.001 | 0.004001 | 0.001 | 4.001 |
| 2.01 | 0.0401 | 0.01 | 4.01 |
| 2.1 | 0.41 | 0.1 | 4.1 |
If direct substitution gave 0 / 0, why is the limit 4?
Experiment: move x towards 2
Use the slider to change x. Watch the numerator, denominator and output change.
What happens when x is exactly 2?
Find the hidden pattern
There is a simpler way to understand the same function.
Remember the algebraic identity:
So we can write:
For x values other than 2, the common factor can be cancelled.
Now when x approaches 2, the simplified expression approaches:
Can we use the simplified expression to find the limit?
Now look at a different function
Consider:
Put x = 2 directly into the expression.
Again, we get 0 / 0. But when x is not equal to 2, we can simplify:
Try nearby values:
| x | g(x) |
|---|---|
| 1.9 | 1 |
| 1.99 | 1 |
| 2.01 | 1 |
| 2.1 | 1 |
What does this tell us?
One more function. A very different result.
Consider:
Direct substitution again gives:
But simplify the expression for x not equal to 2:
As x approaches 2, what does x - 2 approach?
Which conclusion is correct?
See the missing point on a graph
Look at the graph of:
For x not equal to 2, this is the same as y = x + 2.
This missing point is often called a hole in the graph.
Does a missing point always mean the limit does not exist?
The big discovery
You have investigated three functions. All three gave the same result after direct substitution.
| Function | Limit as x approaches 2 |
|---|---|
| (x2 - 4) / (x - 2) | 4 |
| (x - 2) / (x - 2) | 1 |
| (x - 2)2 / (x - 2) | 0 |
What should you do when you get 0 / 0?
- Do not assume the limit is zero.
- Try factorisation and simplification.
- Check values close to the target.
- Study the graph or use another suitable method.
Final challenge
A function gives 0 / 0 when x = 3 is substituted. What can you conclude immediately?
You now understand why 0 / 0 is indeterminate and why limits must be investigated using nearby values or algebraic methods.
Next stage: Continuity - what happens when a graph has a break, a hole or a jump?
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